Question

Simplify


`\left((123)/(321)\right)\left((456)/(654)\right)\left((789)/(987)\right) \left((123)/(321)\right)^(-1)\left((456)/(654)\right)^(-1)\left((789)/(987)\right)^(-1)`

Answer 1

1

Explanation:

using the rule of exponents

`((a)/(b)) ^(-1)` =
`(b)/(a)` , then

`(123)/(321)` ×
`(456)/(654)` ×
`(789)/(987)` ×
`(321)/(123)` ×
`(654)/(456)` ×
`(987)/(789)`

[
`(123)/(321)` ×
`(321)/(123)` = 1 ,
`(456)/(654)` ×
`(654)/(456)` = 1 ,
`(789)/(987)` ×
`(987)/(789)` = 1 ]

= 1 × 1 × 1

= 1