Question

*A 0.145 kg baseball reaches a speed of 36 m/s from rest when a bat strikes. If the average force of 500 N was applied on the ball by the bat, what is the impact time?

Answer 1

Impact time is 0.01 seconds.

Step-by-step explanation:

Express the eventual speed in terms of the average acceleration, impact time and initial velocity (which is 0 in our case):

`v = a\cdot t + v_0 = a\cdot t`

The average acceleration is the result of applying an average force as given. The duration of the impact can be determined as follows:

`v = a\cdot t = (F)/(m)t\implies t=(vm)/(F)= (36(m)/(s)\cdot 0.145 kg)/(500kg(m)/(s^2))=0.010 s`