Question

Find the 10th term in the following arithmetic sequence if the constant being added is

-12:20,8,-12,-16

Answer 1

10th term = -88.

Explanation:

This is an arithmetic sequence with first term = 20 and common difference -12.

nth term = a1 + (n - 1)d

10th term = 20 + (10-1)*-12

= 20 - 108

= -88.

Answer 2

Find the 10th term in the following arithmetic sequence if the constant being added is -12

Explanation:

20 - 12 = 8

8 - 12 = -4

-4 - 12 = -16

So the sequence will be

20; 8; -4; -16

an = 20 - 12(n - 1)

a10 = 20 - 12(10 - 1) = -88