Question

Please answer correctly!!

Answer 1

option-C:

graph-C

Explanation:

we are given

`f(x)=3√(x+1)` if 0<=x<3

`f(x)=5-x` if 3<=x<=5

We can check corner points

At x=0:

`f(0)=3√(0+1)`

`f(0)=3`

so, our point is (0,3)

At x=3:

`f(3)=5-3`

`f(3)=2`

so, our point is (3,2)

At x=5:

`f(5)=5-5`

`f(5)=0`

so, our point is (5,0)

we can see all three points lie on graph-C only

so, graph-C is our graph

Answer 2

Graph C

Explanation:

f(x) = 3 * sqrt(x+1) ,0<x<3

= 5-x , 3 ≤x≤5

Lets see what happens at 3

As it approaches 3 the top equations gives us

f(2.9999999) = 3(sqrt(3+1)) 3*2 = 6 this is an open circle

f(3) = 5-3 = 2

So there is a discontinuity