To solve, use the following equation:
= (y₂ - y₁)/(x₂ - x₁)
Remember that each point contains one x, and one y: (x₁ , y₁) ; (x₂ , y₂)
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4) What is the slope of the line that goes through (6 , 5) and (3 , 1)?
Let:
(x₁ , y₁) = (3 , 1)
(x₂ , y₂) = (6 , 5)
Put the corresponding numbers to the corresponding variable in the equation:
= (y₂ - y₁)/(x₂ - x₁) = (5 - 1)/(6 - 3) = 4/3
is your answer
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5) The slope of the line that goes through (-3 , -5) and (-3 , -6) is ___.
Again, find the slope. Use the equation used above:
= (y₂ - y₁)/(x₂ - x₁)
Let:
(x₁ , y₁) = (-3 , -5)
(x₂ , y₂) = (-3 , -6)
Put the corresponding numbers to the corresponding variable in the equation:
= (y₂ - y₁)/(x₂ - x₁) = (-6 - (-5))/(-3 - (-3))
Remember that two negative = one positive
= (-6 - (-5)/(-3 - (-3) = (-6 + 5)/(-3 + 3)
Simplify.
= (-6 + 5)/(-3 + 3) = -1/0
Because the denominator is 0, the answer is , for there are infinite amount of solutions.
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