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16 votes
If the center of a circle is at (5,-7)
and its radius is 6, complete its
equation:

If the center of a circle is at (5,-7) and its radius is 6, complete its equation-example-1
User Izzo
by
3.8k points

2 Answers

9 votes

Answer:
\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}

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Work Shown:


(h,k) = (5,-7) = \text{center}\\\\r = 6 = \text{radius}\\\\(x - h)^2 + (y - k)^2 = r^2\\\\(x - 5)^2 + (y - (-7))^2 = 6^2\\\\\boldsymbol{(x - 5)^2 + (y + 7)^2 = 36}\\\\

User JorgeSandoval
by
3.6k points
7 votes

The equation is:

(x-5)^2+(y-(-7))^2=36

I hope it helps!

User Ahab
by
3.7k points