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How many liters of 60% alcohol solution should be added to 40 liters of a 20% alcohol solution to make a 50% solution?

User Brentvatne
by
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1 Answer

5 votes

Answer:

120 liters of 60% alcohol solution is needed

Explanation:

Let's assume

x liters of 60% alcohol solution is added

so, we get solution as


=(60)/(100)* x


=0.6x

we are given

40 liters of a 20% alcohol solution is


=40*(20)/(100)


=40*(20)/(100)


=8

so, total alcohol solution is


=8+0.6x

now, we can find total solutions

total solutions is


=x+40

now, it is making 50% solution

so, we get


(8+0.6x)/(x+40) =(50)/(100)

now, we can solve for x


\left(8+0.6x\right)\cdot \:100=\left(x+40\right)\cdot \:50


800+60x=50x+2000


10x=1200


x=120

So,

120 liters of 60% alcohol solution is needed

User Mantosh Kumar
by
8.5k points

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