Question

If a coin is thrown with a starting velocity of 0 m/s down a dry well and hits bottom in 1.2 s, what's the depth of the well?

Answer 1

`H=7.0632m`

Explanation:

Since, a coin is thrown with velocity "u"=0m/s and time "t"=1.2s,it gains an acceleration due to gravity, then using the formula,
`H=ut+(1)/(2)gt^(2)`;

Since u=0 and g=9.81, therefore,

`H=(1)/(2)(9.81)(1.2)^(2)`

`H=(1)/(2)(9.81)(1.44)`

`H=(14.1264)/(2)`

`H=7.0632m`