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What is the equation of a trend that passes through the points (3,95) and (11,12)?

User Rdnobrega
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2 Answers

5 votes

Answer:y= -10.375x+126.25

Explanation:

User Axelarge
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6.2k points
2 votes

The point-slope form:


y-y_1=m(x-x_1)

m - slope

(x₁, y₁) - point

The formula of a slope:


m=(y_2-y_1)/(x_2-x_1)

We have the points (3, 95) and (11, 12). Substitute:


m=(12-95)/(11-3)=-(83)/(8)


\boxed{y-95=-(83)/(8)(x-3)} point-slope form

Convert to the slope-ntercept form (y = mx + b)


y-95=-(83)/(8)(x-3) use the distributivie property


y-95=-(83)/(8)x+(249)/(8) add 95 to both sides


y=-(83)/(8)x+(249)/(8)+95\\\\y=-(83)/(8)x+(249)/(8)+(760)/(8)


\boxed{y=-(83)/(8)x+(1009)/(8)} slope-intercept form

Convert to the standrd form (Ax + By = C)


y=-(83)/(8)x+(1009)/(8) multiply both sides by 8


8y=-83x+1009 add 83x to both sides


\boxed{83x+8y=1009} standard form

User JD White
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5.7k points