Question

Using a table of standard electrode potentials, label each of the following statements as completely

true or false.
A) Cu²+ can oxidize H2, and Fe can reduce Mn²+
B) Ni²+ can oxidize Cu²+, and Fe²+ can reduce H+
C) Fe²+ can oxidize H₂, and Fe²+ can reduce Au³+.
D) Br₂ can oxidize Ni, and H₂ can reduce Mn²+
E) H* can oxidize Fe, and Ni can reduce Br₂

Answer 1

Answer: B and E are True

Step-by-step explanation:

Because Fe has a higher oxidation potential than H2, H+ can oxidize it.

`$\begin{array}{llllll}\mathrm{Fe} & \rightarrow & \mathrm{Fe}^(2+) & +2 \mathrm{e}- & \mathrm{E}^(0)=0.44 \mathrm{~V} \\ \mathrm{H} & \rightarrow & \mathrm{H}^(+) & + & \mathrm{e}^(-) & \mathrm{E}^(0)=0 \mathrm{~V}\end{array}$`

Ni can reduce Br2 because the reduction potential of Ni is more than Br2.

`\mathrm{Ni}^(2+)+2 \mathrm{e}^(-) \rightarrow \mathrm{Ni}^(-) \quad \mathrm{E}^(0)=-0.25 \mathrm{~V}\\2 \mathrm{Br}^(-) \quad \rightarrow \mathrm{Br}_(2)+2 \mathrm{e}^(-) \quad \mathrm{E}^(0)=-1.087 \mathrm{~V}$`