Answer:
The required form in terms of A the value of s is
![s=\sqrt{(A-25)/(16)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/val80iy609x5kb68zgefhpwddf5b3z36jg.png)
Explanation:
Given : The area A of a rectangle parking lot is given by the equation
. Jacob knows the area of the parking lot.
To find : Solve
for s?
Solution :
The area A of a rectangle parking lot is given by the equation
![A=16s^2+25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h3223n8g5y08h783m6z78y6zjhfcw80v6y.png)
To solve the given expression for s, we have to separate the s and take it to one side.
Subtract 25 from both side,
![A-25=16s^2+25-25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5d5hyvg1x80nu524rku1wuv0r64adej0xk.png)
![A-25=16s^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cvjcy7xihn4ij3n55po9u52tbv04s1x9s2.png)
Divide both side by 16,
![(A-25)/(16)=(16s^2)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yuestpu0hpamvtmnyuihvi8aofzjddznxp.png)
![(A-25)/(16)=s^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/obq7u1zm4ubspnxkfdrmvytkg60vm3ntot.png)
Taking root both side,
![\sqrt{(A-25)/(16)}=√(s^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1pnmn97sm5w7cs70fr3f1tv5dfkdul2qdd.png)
![\sqrt{(A-25)/(16)}=s](https://img.qammunity.org/2020/formulas/mathematics/middle-school/42gk7h6nvcek53xy7iigao7isbp6fynlne.png)
So, The required form in terms of A the value of s is
![s=\sqrt{(A-25)/(16)}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/val80iy609x5kb68zgefhpwddf5b3z36jg.png)