Question

What vertical distance will a body dropped from rest fall in 12s of free fall

Answer 1

Distance = (1/2) (gravity) (T-squared)

D = (1/2) (9.8) (12 squared)

D = (4.9) (144)

D = 705.6 meters (NO air resistance)

Answer 2

Distance, s = 705.6 meters

Step-by-step explanation:

We know that, an object will fall freely under the action of gravity. We need to find the distance covered by the body when it is dropped from rest in 12 second of free fall. It can be calculated using second equation of motion as :

`s=ut+(1)/(2)at^2`

u = 0 and a = g

`s=(1)/(2)gt^2`

`s=(1)/(2)* 9.8* (12)^2`

s = 705.6 meters

So, the distance covered by the body in 12 seconds is 705.6 meters. Hence, this is the required solution.