Question

1. Separate the number 58 into three parts so

that the second number is 2 less than the
first number which is one half the third
number.

Answer 1

2nd number = 13

First number = 15

3rd number = 30

Explanation:

Let

2nd number = 1/2x - 2

First number = 1/2x

3rd number = x

Total = 58

x + 1/2x + 1/2x - 2 = 58

x + x+x/2 = 58 + 2

x + 2/2x = 60

x + x = 60

2x = 60

x = 60/2

= 30

x = 30

2nd number = 1/2x - 2

= 1/2*30 - 2

= 15 - 2

= 13

First number = 1/2x

= 1/2*30

= 15

3rd number = x

= 30