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5 votes
Is (0,0) a solution to this system?

y ²x²-4
y< 2x-1
A. No. (0,0) satisfies y 42-4 but does not satisfy y< 2x-1.
B. No. (0,0) does not satisfy either inequality.
C. No. (0,0) satisfies y< 2x- 1 but does not satisfy yz 22.4.
O D. Yes. (0,0) satisfies both inequalities.

Is (0,0) a solution to this system? y ²x²-4 y< 2x-1 A. No. (0,0) satisfies y 42-4 but-example-1
User Drdot
by
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1 Answer

3 votes

Answer:

A. Solution to
y \ge x^2 - 4 but not to
y < 2x - 1

Explanation:

Given


y \ge x^2 - 4


y < 2x - 1

Required

Is
(0,0) a solution?


(0,0) implies that:


x = 0\ and\ y = 0

To check if it is a solution or not, we simply substitute 0 for x and for y in the given inequalities


y \ge x^2 - 4 becomes


0 \ge 0^2 - 4


0 \ge 0- 4


0 \ge - 4

This solution is true


y < 2x - 1 becomes


0 < 2 * 0 - 1


0 < 0 - 1


0 < - 1

This solution is not true because 0 is greater than 1.

Hence, option (A) is correct

User Robina Li
by
7.7k points
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