Question

I would like to know why this is the correct answer

-A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N?

*The acceleration decreases to a quarter of its original value, or about 0.13 m/s2.

Answer 1

A spring scale shows a net force of 0.8 N acting on a 1.5-kg mass. What happens to the acceleration of the object if the net force is decreased to 0.2 N? A, The acceleration decreases to a quarter of its original value, or about 0.13 m/s².

Answer 2

The acceleration of the object if the net force is decreased = 0.13 m/s²

Further explanation

Given

A net force of 0.8 N acting on a 1.5-kg mass.

The net force is decreased to 0.2 N

Required

The acceleration of the object if the net force is decreased

Solution

Newton's 2nd law :

`\tt \sum F=m.a`

The mass used in state 1 and 2 remains the same, at 1.5 kg

• state 1

ΣF=0.8 N

m=1.5 kg

The acceleration, a:

`\tt a=(\sum F)/(m)\\\\a=(0.8)/(1.5)\\\\a=0.53`m/s^2`

• state 2

ΣF=0.2 N

m=1.5 kg

The acceleration, a:

`\tt a=(\sum F)/(m)\\\\a=(0.2)/(1.5)\\\\a=0.13~m/s^2`