Question

An aqueous solution contains

32.7% KCI (weight/weight %).
What is the mole fraction of KCI in
this aqueous solution?
Molar Mass
KCI: 74.55 g/mol
H2O: 18.016 g/mol

Answer 1

32.7

Step-by-step explanation:

Answer 2

The mole fraction of KCl = 0.105

Further explanation

Given

%w/w KCl = 32.7

Required

the mole fraction of KCI

Solution

For 100 g solution : KCl = 32.7 g, H₂O = 67.3 g

mol KCl :

`\tt (32.7)/(74.55~g/mol)=0.439`

mol H₂O :

`\tt (67.3)/(18.016)=3.74`

total mol of solution = 0.439+3.74=4.179

mol fraction of KCl :

`\tt (0.439)/(4.179)=0.105`