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if the evaporator oulet temperature on an r-410A system is 50f and the evaporator superheat is 10f, what is the evaporating pressure of the refrigerant in the system

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Answer: 143 psig

Step-by-step explanation:

Given data:

System heat = 50f

Evaporator superheat = 10f

System = r410a.

Solution:

Evaporating pressure of the refrigerant in the system

= system heat - evaporator superheat.

= 50f - 10f

= 40f.

Using the r-410a temperature chart

40f = 143 psig.

User JonLim
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