Question

What is the equation of the line

that passes through the point
(-3,-5) and is parallel to the line
2x+3y=15

Answer 1

y = (-2/3)*x -7

Explanation:

2x+3y=15

3y = -2x + 15

y = (-2/3) *x + 5

slope for parallel line should be -2/3 too

pass (-3 , -5) y = mx + b b = y - mx = (-5) - ((-2/3) * (-3))

b = -5 - 2 = -7

parallel line: y = (-2/3)*x -7

Answer 2

ANSWER: Y=2x+1. The formula of ur answer would be in y=mx+b. Since it is parallel to 2x+3y=15, the m would have to be the same. Therefore m =2. Next we find b. We would plug in the points (-3,-5) in the formula y=mx+b to find B knowing m= 2 so -5=2(-3)+b. B=1.