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If 3 cars have traveled a total of 180,000 miles and the distance traveled by each car differs by at least 1 mile from the distance traveled by either of the other 2 cars,what is the minimum possible number of miles traveled by the car with the most mileage

User Fooser
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1 Answer

5 votes

Answer:

60001 miles

Explanation:

Given


Total\ Distance = 180000

Let the cars be:
Car\ A, Car\ B\ and\ Car\ C

Assume that Car A has the minimum mileage of x.


Car\ A = x

The other cars would be:


Car\ B = x + 1


Car\ C = x + 2

This implies that Car C has the highest mileage

Required

Determine the possible minimum number of miles

Since the total distance is 180000, then:


Car\ A + Car\ B + Car\ C = 180000

Substitute values for Car A, B and C


x + x + 1 + x + 2 = 180000

Collect Like Terms


x + x + x = 180000-1-2


3x = 179997

Divide both sides by 3


(3x)/(3) = (179997)/(3)


x = (179997)/(3)


x = 59999

The car with the most mileage is Car C

So:


Car\ C = x + 2

Substitute 59999 for x in
Car\ C = x + 2


Car\ C = 59999 + 2


Car\ C = 60001

The minimum distance travelled by Car C is 60001 miles

User Joshua Hyatt
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