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If $m \Diamond n = (m^2 - n) \div n$ for all real numbers $m$ and $n$, where $n \\eq 0$, what is the value of $6 \Diamond 3$?

User Roy J
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1 Answer

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By definition of ◇, you have

6 ◇ 3 = (6² - 3)/3 = (36 - 3)/3 = 33/3 = 11

User Emeka
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