Question

What is the period of a pendulum near Earth’s surface that is 130 cm long?

Question 1 options:

2.3 s

0.83 s

9.1 s

22.9 s

Answer 1

A). 2.3 s

Step-by-step explanation:

Given that,

Length of the string = 130cm or 1.3 m

g near Earth's surface = 9.8
`ms^(-2)`

To determine the period of a pendulum near Earth’s surface;

T = 2 π
`\sqrt{(L)/(g) }`

T = 2π
`\sqrt{(1.3)/(9.8) }`

T = 2.3 sec

Therefore, the period of the pendulum near the earth's surface is 2.3 sec.