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Solve for [x]. The polygons in each
2x-20
16
16
8

Solve for [x]. The polygons in each 2x-20 16 16 8-example-1
User Nasmorn
by
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1 Answer

5 votes


\quad \huge \quad \quad \boxed{ \tt \:Answer }


\qquad \tt \rightarrow \:x = 16

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\large \tt Solution \: :

If two polygons are similar, their corresponding sides ratios will be equal to each other.


\qquad \tt \rightarrow \: \cfrac{8}{16} = \cfrac{2x - 20}{24}


\qquad \tt \rightarrow \: \cfrac{1}{2} = \cfrac{2x - 20}{24}


\qquad \tt \rightarrow \: 2x - 20 = \cfrac{24}{2}


\qquad \tt \rightarrow \: 2x = 12 + 20


\qquad \tt \rightarrow \: 2x = 32


\qquad \tt \rightarrow \: x = 16

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

User Thomas Braun
by
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