Question

Find the equation of a line parallel to y = 3x - 6, passing through the point (-6, -7).

y = 3x + 11


y = 3x - 11


y = 3x - 7


y = -1/3x - 9

Answer 1

Parallel lines have the same a slope. Therefore if

k: y = 3x - 6 → slope = 3

and l: y = mx + b

l || k ⇔ m = 3

l: y = 3x + b

We have the point (-6, -7). Put the coordinates to the equation:

-7 = 3(-6) + b

-7 = -18 + b add 18 to both sides

11 = b → b = 11

Answer: y = 3x + 11