Question

A. Two paths of width 2m each run across the middle of a rectangular

garden of length 60m and breadth 40m. What is the total area
covered by the both paths.
b. The area of a rectangular field is 60000 m². If the ratio of length
and breadth is 3:2, find its perimeter.

Answer 1

196 m² ; 1000 m

Explanation:

Given that:

Dimension of rectangular garden = 60m by 40m

Width of the 2 paths that run across each other = 2m

Hence,

Area of path 1 = (length * width) = (60 * 2) = 120m²

Area of path 2 = (breath * width) = (40 * 2) = 80m²

Area of Point where both paths cross each other (2 * 2) = 4m²

Total area covered by both path = (120m² + 80m² - 4m²) = 196m²

B.)

Area of rectangular field = 60000m²

Ratio of length and breadth = 3 : 2

Length * breadth = 60000

x ; breadth = (2/3)x

x * (2/3)x = 60000

2/3 x² = 60000

x² = 60000 ÷ 2/3

x² = 40,000

x = sqrt(40000)

x = 200

(3/2) * 200 = 300

Length = 300

Hence,

Perimeter = 2(length + breadth)

Perimeter = 2(300 + 200)

Perimeter = 2(500)

Perimeter = 1000m