9514 1404 393
Answer:
25.5 cm
Explanation:
If the walk is x meters wide, it adds 2x to the overall length and width. Then the area of the walkway is ...
(2x +5)(2x +6.25) -(5)(6.25) = 6
4x^2 +22.5x = 6 . . . . simplify left side
4x^2 +22.5x -6 = 0 . . . subtract 6 to put into standard form
Using the quadratic formula, the walkway width can be found to be ...
x = (-22.5 +√(22.5² -4(4)(-6)))/(2(4)) = (-22.5 +√602.25)/8
x ≈ 0.25510
The border width should be about 25.5 cm.