Answer: sin
= ±
Explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A =
& cos a=
,thus we get
sin
=±
∴ sin
=±
= ±
since ,360° <
<450°
,180° <
<225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!