Question

3. What mass of water vapor condenses if 435 kJ of heat are released in the process? a a 10.79 b 982 g C 1.30 x 10 g d 1939​

Answer 1

Mass of water vapor = 193 g

Further explanation

Given

435 kJ of heat are released

Required

mass of water vapor

Solution

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lv for water = 2256 kJ/kg or 2256 J/g or 40.7 kJ/mol

So the mass of water vapor :

`\tt m=(Q)/(Lv)\\\\m=(435000~J)/(2256~J/g)\\\\m=192.8\approx 193~g`