Question

Write the help of given diagram calculate the current through each resistor..​

Answer 1

`i_A` = 3 A

`i_B` = 1.8 A

`i_C` = 1.2 A

Step-by-step explanation:

Combined resistance of the resisters B and C,

`(1)/(R')=(1)/(R_1)+(1)/(R_2)` [Since
`R_1` and
`R_2` are attached in parallel]

`(1)/(R')=(1)/(4)+(1)/(6)`

`(1)/(R')=(10)/(24)`

R' = 2.4 Ω

Since, R' and resistor A are in series therefore, total resistance of both the resistors = 2 + 2.4

= 4.4 Ω

Now the current flowing in the circuit 'i' =
`(E)/(R+r)`

Here, E = E.M.F. of the cell

R = Total resistance of all resistors attached

r = Resistance of the cell

'i' =
`(9)/(2.4+0.6)`

i = 3 A

Current flowing in resistor A = 2 A

And Current in combined resistance of B and C = 3 A

Current flow in the resistors B and C will be in the ratio of C : B,

`(i_C)/(i_B)=(B)/(C)`

`(i_C)/(i_B)=(4)/(6)`

`(i_C)/(i_B)=(2)/(3)`

Therefore,
`i_C` =
`(2)/((2+3))* 3` = 1.2 A

`i_B=(3)/((2+3))* 3` = 1.8 A