Answer:
The mass of the second player is 72.73 kg
Step-by-step explanation:
Given;
mass of the first player, m₁ = 100 kg
velocity of the first player, u₁ = 4 m/s
velocity of the second player, u₂ = 5.5 m/s
let the mass of the second player = m₂
Since they have equal momentum, the mass of the second player will be obtained by equating their momentum.
m₁u₂ = m₂u₂
100 x 4 = 5.5m₂
400 = 5.5m₂
m₂ = 400 / 5.5
m₂ = 72.73 kg
Therefore, the mass of the second player is 72.73 kg