Question

The vertices of AJKL are J(-3, -2), K(1, 4), and L(4, 2). Which coordinate pairs are vertices of D5(^JKL)? Select all that apply.

Answer 1

J’ = (-15, -10)

K’ = (5, 20)

L’ = (20, 0)

Explanation:

Answer 2

Given:

The vertices of ΔJKL are J(-3, -2), K(1, 4), and L(4, 2).

To find:

The coordinate pairs of vertices of
`D_5(\Delta JKL)`.

Solution:

We know that,
`D_5(\Delta JKL)` means triangle JKL dilated by scale factor 5 with origin as center of dilation.

If a figure is dilated by factor k and origin is the center of dilation, then

`(x,y)\to (kx,ky)`

From the given problem, the rule of dilation is

`(x,y)\to (5x,5y)`

Now,

`J(-3,-2)\to J'(5(-3),5(-2))=J'(-15,-10)`

`K(1,4)\to K'(5(1),5(4))=K'(5,20)`

`L(4,2)\to L'(5(4),5(2))=L'(20,10)`

Therefore, the coordinate pairs of vertices of
`D_5(\Delta JKL)` are J'(-15,-10), K'(5,20) and L'(20,10).