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Solve 3cosx-1,0<=x<=pi/2

User Rakin
by
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1 Answer

2 votes

Answer:

E(-9)≈3.4936

Explanation:

Calculate the arc length of the following curve from x = 0 to x = π/2:

y(x) = -1 + 3 cos(x)

Hint: | The definition of arc length in Cartesian coordinates is s = integral_(x_0)^(x_1) sqrt(1 + y'(x)^2) dx.

Apply the definition of arc length to y(x) = -1 + 3 cos(x) for 0<x<π/2:

s = integral_0^(π/2) sqrt(1 + (d/dx(-1 + 3 cos(x)))^2) dx

Hint: | What is d/dx(-1 + 3 cos(x))?

Compute the derivative d/dx(-1 + 3 cos(x)):

= integral_0^(π/2) sqrt(1 + (-3 sin(x))^2) dx

Hint: | Can the integrand be simplified?

Simplify sqrt(1 + (-3 sin(x))^2):

= integral_0^(π/2) sqrt(1 + 9 sin^2(x)) dx

Hint: | Can this integral be computed?

Compute the definite integral:

Answer: E(-9)≈3.4936

User Nas Banov
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5.1k points