Question

When the volume of a gas is

changed from 3.6 L to 15.5 L, the
temperature will change from
°C to 87°C.
Assume that the number of moles and the
pressure remain constant.
Be sure to notice that temperatures are
given in °C!

Answer 1

Initial temperature = -189.4 °C

Further explanation

Given

the volume of a gas is changed from 3.6 L to 15.5 L

final temperature = 87 °C = 87+ 273 = 360 K

Required

initial temperature

Solution

Charles's Law

When the gas pressure is kept constant, the gas volume is proportional to the temperature

`\tt (V_1)/(T_1)=(V_2)/(T_2)`

`\tt T_1=(V_1.T_2)/(V_2)\\\\T_1=(3.6* 360)/(15.5)\\\\T_1=83.6~K=-189.4^oC`