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How many moles of O, will occupy 1.00 L at a temper-

ature of -118°C and a pressure of 49.77 atm?

1 Answer

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Moles of O₂ = 3.92

Further explanation

Given

V=1 L

T=-118 °C + 273 = 155 K

P = 49.77 atm

Required

moles of O₂

Solution

the gas equation can be written


\large {\boxed {\bold {PV = nRT}}}

where

P = pressure, atm

V = volume, liter

n = number of moles

R = gas constant = 0.08206 L.atm / mol K

T = temperature, Kelvin

Input the value :

n= PV/RT


\tt n=(49.77~atm* 1~L)/(0.082* 155)=3.92~moles

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