Moles of O₂ = 3.92
Further explanation
Given
V=1 L
T=-118 °C + 273 = 155 K
P = 49.77 atm
Required
moles of O₂
Solution
the gas equation can be written

where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
Input the value :
n= PV/RT
