Question

How many solutions does the system of equations below have?
y = 3x + 4
y + 6 = 3x

Answer 1

0 / no solutions

Explanation:

Rewrite both in terms to the form y = equation.

EQ1: y = 3x + 4 (already in correct form)

EQ2: y = 3x - 6 (subtracting 6 from both sides).

Now suppose there is an intersection, then:

3x + 4 = 3x - 6, subtracting 3x from both sides gives:

4 = -6, which is a contradiction!

Therefore there are 0 / no solutions