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Problem (11), 10 points 3 Math majors and 3 Computer Science majors will be presenting at a conference. Three students will be randomly selected to present on Monday, and the remaining three stu- dents will present on Tuesday.

(a, 3 points) What is the probability that two Computer Science majors and a math major will present on Tuesday? You do not need to simplify your answer.
(b, 5 points) Suppose we know at least one Math major has been selected to present on Monday. What is the probability that two Computer Science majors and a math major will present on Tuesday, given this information?
(c, 2 points) Based on your answer for b, are the events ‘at least one math major is selected to present on Monday' and 'two computer science majors and a math major present on Tuesday' independent?

User RickyA
by
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1 Answer

2 votes

Answer:

a}
P_1= 0.3

b)
P_2 =0.45

c) NOT INDEPENDENT

Explanation:

From the question we are told that

Sample space

Math majors are 3

computer science majors are 3

Generally the sample space is

Mathematically the sample space required on Monday is given as
S_m= 3c_1 * 3C_2

where
S_m =sample space on Monday

Therefore,


P_1 =
(3C_1 *3C_2)/(6C_3)


P_1=(3*3)/(20)


P_1=(6)/(20)

b)

Generally the the equation is given as


P_2 =P((x \cap y)/(y))

where

x is selecting two math major and 1 computer science major on Monday

y is at leas one math major selected


P_2 =(^3C_1*^3C_2)/(^3C_1*^3C_2 + ^3C_2*^3C_1 +^3C_3*^3C_0)


P_2 =(3*3)/(3*3 + 3*3 +^1*1)

c)

Generally in representing independent events


P_3=p(x \cap y)

=>
p(x) * p(y)

Mathematically


n(x)= ^3C_1 *^3C_2


n(y)={^3C_1*^3C_2 + ^3C_2*^3C_1 +^3C_3*^3C_0}

therefore


n(x \cap y) =^3C_1 *^3C_2

This does not satisfy the two equations stated above therefore NOT INDEPENDENT

User Marisel
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7.9k points