Question

The length of a rectangle deck is 3 times its width. If the deck's perimeter is 16 ft, what is the deck's area?

Answer 1

12 sq ft

Explanation:

let w = width

let 3w = length

w + w + 3w + 3w = 16

8w = 16

x = 2

Area = 3(2) x 2

A = 6 x 2

Answer 2

Answer:12

Explanation:

3x+3x+x+x=16

8x=16 so x =2

2*3=6 6*2=12