Question

What is the mass of H2o required to dissolve 14.5g of glucose

if the molality of solution is 0.24 molal​

Answer 1

Mass of water = 0.33 Kg

Step-by-step explanation:

Given data:

Mass of water = ?

Mass of glucose = 14.5 g

molality of solution = 0.24 m

Solution:

Number of moles of glucose:

Number of moles = mass/molar mass

Number of moles = 14.5 g/ 180.156 g/mol

Number of moles = 0.08 mol

Mass of water:

Molality = number of moles of solute / Kg of solvent

0.24 m = 0.08 mol / Kg of solvent

Kg of solvent = 0.08 mol / 0.24 m

Kg of solvent = 0.33 Kg