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What is the 5th term of an arithmetic sequence of 20 terms with first and last terms of 2 and 59, respectively

2 Answers

5 votes

Answer:

14

Explanation:

User Simon Willison
by
8.7k points
3 votes

Answer:

14

Explanation:

aₙ = a₁ + (n-1)*d

59 = 2 + (20-1) * d

59 = 2 + 19d

19d = 59-2 = 57

d = 3

5th term: a₅ = 2 + 4 * 3 = 14

User Hekevintran
by
8.1k points

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