Answer:
8009 N
Step-by-step explanation:
Given that a 1370-kg small aircraft accelerates along the runway from 7.4 m/s to 37.8 m/s in 5.20 seconds. Determine the net force acting upon the plane. (Assume that its engine/propeller makes no contributes to its forward motion)
According to the definition of acceleration, acceleration is the change in velocity per time taken.
Acceleration a = ( 37.8 - 7.4 )/ 5.2
Acceleration a = 30.4 / 5.2
Acceleration a = 5.846 m/s^2
Force = mass × acceleration
Force = 1370 × 5.846
Force = 8,009 N
Therefore, the net force acting upon the plane is 8009 N. (Assume that its engine/propeller makes no contributes to its forward motion)