86.1k views
0 votes
assume that the variable under consideration has a density curve. it is given that 27.1% of all possible observations of the variable are less than 17. Determine the area under the density curve that lies to the right of 17.​

User Mmagnuski
by
8.7k points

1 Answer

7 votes

Answer:

72.9%

Explanation:

Given that :

27.1% of all possible observation of a certain variable are less than 17 ;

That is ;

Let variable = y ;

Proportion of (y < 17) = 27.1% = (27.1 / 100) = 0.271

Proportion that lies to the right :

P(y > 17) = 1 - P(y < 17)

P(y > 17) = 1 - 0.271

P(y > 17) = 0.729 = 72.9%

User Jacek
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories