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Prove the following identities b.tanA/1+secA=tanA/2

Prove the following identities b.tanA/1+secA=tanA/2
132k views
3 votes
Prove the following identities
b.tanA/1+secA=tanA/2

User Ragesh Chakkadath
by
7.8k points

1 Answer

5 votes

Answer:


(tanA)/(1+secA) = tan ((A)/(2) )

Step-by-step explanation:

Given

=
(tanA)/(1+secA)


= ((sinA)/(cosA) )/((1+cosA)/(cosA) )

=
(sinA)/(1+cosA) = (2sin(A)/(2) cos(A)/(2) )/(2cos^(2) (A)/(2) )


= tan(A)/(2)

User Mangokun
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