2 Answers

Shaswat Rungta · Answer 1 · 2021-11-11T23:46:01+0000

Answer:

4500W

Step-by-step explanation:

$P = {I}^(2) R$

where P = Power consumed , I = Current & R = Resistance.

In the question it's given that

I = 15A ; R = 20Ω

So ,

$P = {15}^(2)* 20 = 225 * 20 = 4500W$

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