Answer:
x = +/-pi/3 or x = -pi/3 or (4/3)pi
Explanation:
2sin(2x)-2sinx+2sqrt3cosx-sqrt3 = 0
4sinxcosx - 2sinx + 2sqrt(3)cosx - sqrt(3) = 0
2sin(x)[2cos(x)-1] + sqrt(3)[2cos(x)-1] = 0
[2cos(x)-1][2sin(x)+sqrt(3)] = 0
2cos(x)-1 = 0 or 2sin(x)+sqrt(3) = 0
cos(x) = 1/2 or sin(x) = -sqrt(3)/2
x = +/-pi/3 or x = -pi/3 or (4/3)pi