Answer:
The standard form of the given equation is f(x) = 0x²-4x+15=0
Explanation:
The standard form is ax²+bx+c=0
Given f(x) = -4(x-2)+ 7
we can write the standard form
= 0x² -4(x-2)+7 =0
⇒ 0x² -4x +8 +7 =0
⇒ 0x² -4x + 15 =0
now comparing the standard form ax²+bx+c=0
a = 0 , b= -4 and c =15