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A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?

User JanD
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1 Answer

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Answer:


2.33\ m/s^2

Step-by-step explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:


\displaystyle a=(Fn)/(m)


\displaystyle a=(3500)/(1500)


\boxed{a = 2.33\ m/s^2}

The car's acceleration is
a = 2.33\ m/s^2

User Shailendra Madda
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