Question

Dy÷dx=(x-1)(x+3) at x=2 first principal ​

Answer 1

dy/2d=(2-1)(2+3)

dy/2d=4+6-2-3

dy/2d=5

dy=5(2d)=10d

2d=5/dy

dy=5×(5/dy)= 25/dy

2d=5/dy

dy^2=25

dy=√25=5

2d=5/dy=5/5=1

d=1/2

dy=1/2×10=5 y=10

plug all of the values

5/(1/2×2)=5

=

4+6-2-3=5

so finally: 5=5

any questions?

Answer 2

δy

δx = 2x − 4 + δx;

and the limit as δx → 0 is

dy

dx = lim

δx→0

µδy

δx¶

= 2x − 4.

Explanation: