Question

A typical home instant pot has an internal volume of 6.5 Liters. If the steam inside an instant pot with an internal pressure of 191.0 kPa and a temperature of 750.0 K was released into the atmosphere at 101.3 kPa and 298K, what volume with the steam occupy in the atmosphere?

Answer 1

Answer: V2 = 4.8696 L is the volume occupied by the steam in the atmosphere

We can use the combined gas law to solve this problem.

Combined gas law: P1 V1 / T1 = P2 V2 / T2

(191.0 kPa)(6.5 L) / (750.0 K) = (101.3 kPa)(V2) / (298 K)

Now we solve for V2;

1241.5 / 750 = 101.3 / 298

Now we cross-multiply;

369967 = 75975x

Divide by 75975 on each side;

369967 / 75975 = 75975x / 75975

Round our answer to sig figs;

x (aka V2) = 4.8696 L is the volume occupied by the steam in the atmosphere