Question

Building A is 400 feet tall and Building B is 300 feet tall. Johnny is standing in between the two building. The angle of elevation from the point on the ground where Johnny is standing is 70 degrees to the top of Building A and 52 degrees to the top of Building B. How far apart are the two buildings

Answer 1

389 feets apart

Explanation:

Given that:

Building A

Height = 400feets

Angle of elevation = 70°

Building B:

Height = 300 feets

Angle of elevation = 52°

Distance from the foot of building A to where Jonny is standing = x (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 70 = 400/ x

2.7474774x = 400

x = 145.58809 feets

Distance from the foot of building B to where Jonny is standing = y (see attached picture)

Using trigonometry :

Tanθ = opposite / Adjacent

Tan 52 = 300/ y

1.2799416y = 300

y = 145.59

y = 234.38568 feets

x + y = distance between the two buildings

(145.58809 + 234.38568) feets

= 379.97377

= 380 feets apart