Answer:
P = 1412.82 [Watt]
Step-by-step explanation:
First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.
![m=30+30+20\\m= 80 [kg]](https://img.qammunity.org/2021/formulas/physics/high-school/f2ngxs0zzw4i8pt88rfx2peilm9wvzqh0c.png)
Weight is now defined as the product of mass by gravitational acceleration.
![w=m*g](https://img.qammunity.org/2021/formulas/physics/high-school/ilevc2pjqnwwtzc015pxj5yzk6xdiqrmo4.png)
where:
m = mass = 80 [kg]
g = gravity acceleration = 9.81 [m/s²]
![w=80*9.81\\w=784.8[N]](https://img.qammunity.org/2021/formulas/physics/high-school/mdm2jfoc960og9jk3f39kikhrq83ejkg62.png)
Now using the product of the weight by the distance traveled we can calculate the work.
![W=w*d](https://img.qammunity.org/2021/formulas/physics/high-school/sq4v6af9t3lggymt3ne70kbgo3dc83vwwi.png)
where:
W = work [J]
w = weight = 784.8 [N]
d = distance = 0.9 [m]
![W=784.8*0.9\\W=706.41[J]](https://img.qammunity.org/2021/formulas/physics/high-school/54ijqo26j4vx01yuk4selpmkjs7a807foh.png)
And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.
![P=W/t\\P=706.41/0.5\\P=1412.82[W]](https://img.qammunity.org/2021/formulas/physics/high-school/6kdr03qxcyc7hvfaddhfjhh5n9xnd3vam9.png)