Answer:
0.59 g
Step-by-step explanation:
The reaction at the first cathode;
Ag^+(aq) + e -----> Ag
if Q = It = 1.5 * 10 * 60 = 900C
According to Faraday's second law of electolysis; if we pass the same quantity of electricity through different electrolytes, the mass of substances deposited on each cathode is proportional to the equivalent weights.
Equivalent weight E = Atomic mass/valency
For Ag = 108/1 = 108
For Ni = 59/2 = 29.5
Hence
Let m1 = mass of Ag deposited =2.16
Let m2 = mass of Ni deposited
Let E1 = equivalent weight of Ag
Let E2 = equivalent weight of Ni
m1/m2 = E1/E2
2.16/m2 = 108/29.5
m2 = 2.16 * 29.5/108
m2 = 0.59 g